document.write( "Question 893414: For the polynomial, list each real zero and its multiplicity. Determine whether the graph crosses or touches the x-axis at each x -intercept. f(x)= (x+1/5)^4(x-1)^3\r
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document.write( "Given Answers are:
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document.write( "a. -1/5, multiplicity 4, touches x-axis;1, multiplicity 3, crosses x-axis
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document.write( "b. 1/5, multiplicity 4, touches x-axis; -1, multiplicity 3, crosses x-axis
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document.write( "c. 1/5, multiplicity 4, crosses x-axis; -1, multiplicity 3, touches x-axis
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document.write( "d. -1/5, multiplicity 4, crosses x-axis; 1, multiplicity 3, touches x-axis
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Algebra.Com's Answer #541271 by Theo(13342)![]() ![]() You can put this solution on YOUR website! equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x)= (x+1/5)^4 * (x-1)^3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have 2 roots.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first root is at x = 1/5 and has a multiplicity of 4 which means that the graph will touch the x-axis at that point but not cross it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the second root is at x = 1 and has a multiplicity of 3 which means that the graph will cross the x-axis at that point.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's the graph of your equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you solution is selection a.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can see that the graph touches the x-axis at x = -1/4 and the graph crosses the x-axis at x = 1.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |