document.write( "Question 893227: an alloy was machined into a flat disk 31.5 mm in diameter and 4.5 mm thick. a hole 7.5 mm in diameter was drilled through the center. the disk weighed 20.2 g. what was the density of the alloy in SI units? \n" ); document.write( "
Algebra.Com's Answer #541259 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Find the volume of the new part.
\n" ); document.write( "The volume is the difference of the two circular areas multiplied by the thickness.
\n" ); document.write( "
\n" ); document.write( "\"V=1053pi\"\"mm%5E3\"
\n" ); document.write( "Converting to \"m%5E3\",
\n" ); document.write( "\"V=1053pi%2A10%5E%28-9%29\"\"m%5E3\"
\n" ); document.write( "The mass in kg would be
\n" ); document.write( "\"m=20.2%2F1000=2.02%2A10%5E%28-2%29\"\"kg\"
\n" ); document.write( "So the density is,
\n" ); document.write( "\"rho=m%2FV=%282.02%2A10%5E%28-2%29%29%2F%281053pi%2A10%5E%28-9%29%29\"
\n" ); document.write( "\"rho=6106\"\"kg%2Fm%5E3\"
\n" ); document.write( "
\n" );