document.write( "Question 893368: Write the general term for the following sequences:\r
\n" ); document.write( "\n" ); document.write( "1. 1/2, 1/3, 1/4, 1/5, ...
\n" ); document.write( "2. 1, 8, 27, 64, ...
\n" ); document.write( "3. 7, 7, 7, 7, ...
\n" ); document.write( "4. 1/11, 2/12, 3/13, 4/14, ...
\n" ); document.write( "5. 9, 99, 999, ...
\n" ); document.write( "6. 1, 1, 2, 3, 5, 8, ...
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Algebra.Com's Answer #541226 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Number 2:\r
\n" ); document.write( "\n" ); document.write( "Factorize each term.
\n" ); document.write( "\"1\"....?
\n" ); document.write( "\"8=2%5E3\"
\n" ); document.write( "\"27=2%5E3\"
\n" ); document.write( "\"64=8%2A8=2%5E3%2A2%5E3\" or \"2%5E6=4%2A4%2A4=4%5E3\"
\n" ); document.write( "The rule appears for any n term, general term is \"n%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "Number 6:\r
\n" ); document.write( "\n" ); document.write( "The sequence depends on the first two terms. The n=1 and the n=2 terms are both 1. The sequence follows as any n term is the n-1 term plus the n-2 term. If you want to call any term as \"T%5Bn%5D\", then any n term starting at n=3 will be \"T%5Bn%5D=T%5Bn-1%5D%2BT%5Bn-2%5D\".
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