document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=893340>Question 893340</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is twice as long as it is wide. What is the perimeter if its area is 32 cm2?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #541207 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=541207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = width<BR>\n" );
document.write( "2x = length  {it is twice as long as it is wide}\r<BR>\n" );
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document.write( "Area of a rectangle = width x length\r<BR>\n" );
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document.write( "x(2x) = 32 {substituted width and length into area formula}<BR>\n" );
document.write( "2x² = 32 {multiplied}<BR>\n" );
document.write( "x² = 16 {divided each side by 2}<BR>\n" );
document.write( "x = 4 {took square root of each side}<BR>\n" );
document.write( "2x = 8 {substituted 4, in for x, into 2x}\r<BR>\n" );
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document.write( "width = 4 cm<BR>\n" );
document.write( "length = 8 cm\r<BR>\n" );
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document.write( "Perimeter of a rectangle = 2(width) + 2(length)<BR>\n" );
document.write( "= 2(4) + 2(8) {substituted 4 for width and 8 for length}<BR>\n" );
document.write( "= 8 + 16 {multiplied}<BR>\n" );
document.write( "= 24 {added}\r<BR>\n" );
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document.write( "Perimeter = 24 cm<BR>\n" );
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