document.write( "Question 893148: In the January of the year 2000, I was one more than eleven times as old as my son William. In January of 2009, I was 7 more than 3 times as old as him. How old was my son in January of 2000? \n" ); document.write( "
Algebra.Com's Answer #541194 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let a = his age in yr 2000 \n" ); document.write( "Let w = Will's age in yr 2000 \n" ); document.write( ": \n" ); document.write( " In the January of the year 2000, I was one more than eleven times as old as my son William. \n" ); document.write( "a = 11w + 1 \n" ); document.write( ": \n" ); document.write( "In January of 2009, I was 7 more than 3 times as old as him. \n" ); document.write( "(nine yrs later) \n" ); document.write( "a + 9 = 3(w+9) + 7 \n" ); document.write( "a + 9 = 3w + 27 + 7 \n" ); document.write( "a = 3w + 34 - 9 \n" ); document.write( "a = 3w + 25 \n" ); document.write( ": \n" ); document.write( "Replace a with (11w+1) from the 1st statement \n" ); document.write( "11w + 1 = 3w + 25 \n" ); document.write( "11w - 3w = 25 - 1 \n" ); document.write( "8w = 24 \n" ); document.write( "w =- 24/8 \n" ); document.write( "w = 3 yrs old, Will in yr 2000 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, find a \n" ); document.write( "a = 11(3)1 \n" ); document.write( "a = 34 yrs old in 2000 \n" ); document.write( "Check in the 2nd statement \n" ); document.write( "34 + 9 = 3(3 + 9 ) + 7 \n" ); document.write( "43 = 36 + 7\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |