document.write( "Question 887965: Five hundred depth readings for an inland lake were normally distributed with a mean of 62 feet and a standard deviation of 8.5 feet. What percent of the depths were between 53.5 feet and 70.5 feet? \n" ); document.write( "
Algebra.Com's Answer #541142 by tommyt3rd(5050)![]() ![]() You can put this solution on YOUR website! z1=(53.5-62)/8.5=-1 \n" ); document.write( "z2=(70.5-62)/8.5=1\r \n" ); document.write( "\n" ); document.write( "P(-1 < z < 1)=0.6826\r \n" ); document.write( "\n" ); document.write( "about 68% \n" ); document.write( " |