document.write( "Question 893074: A Carpenter and a helper can do a certain job in 15 days. If the Carpenter works 1.5 times as fast as the helper, how long would it take each to do the job, working alone? \n" ); document.write( "
Algebra.Com's Answer #541104 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! h=1.5c \n" ); document.write( "1/c+1/1.5c=1/15\r \n" ); document.write( "\n" ); document.write( "multiply by 15c\r \n" ); document.write( "\n" ); document.write( "15+15/1.5=c \n" ); document.write( "15+10=c \n" ); document.write( "c=25 \n" ); document.write( "h=37.5 \n" ); document.write( "check \n" ); document.write( " 1/25+1/37.5=1/15 \n" ); document.write( "2/50+2/75=2/30 \n" ); document.write( "6/150+4/150=10/150 \n" ); document.write( "ok\r \n" ); document.write( "\n" ); document.write( "but \n" ); document.write( "(3/2)r+r=1/15 \n" ); document.write( "45/2r+15r=1 \n" ); document.write( "3r+2r=2/15 \n" ); document.write( "45r+30r=2 \n" ); document.write( "75r=2 \n" ); document.write( "r=2/75 \n" ); document.write( "r=1/37.5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |