document.write( "Question 893132: How many milliliters of pure acid must be added to 150 milliliters of a 30% acid solution to obtain a 40% acid solution
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Algebra.Com's Answer #541086 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many milliliters of pure acid must be added to 150 milliliters of a 30% acid solution to obtain a 40% acid solution \n" ); document.write( " ----------------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.30*150 + 1*x = 0.40(150+x) \n" ); document.write( "------ \n" ); document.write( "30*150 + 100x = 40*150 + 40x \n" ); document.write( "60x = 10*150 \n" ); document.write( "x = (1/6)150 \n" ); document.write( "x = 25 mm (amt of pure acid needed) \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |