document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=893042>Question 893042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man travels from a to b at 4km/h and from b to a at 6km/h.the total journey takes 45 minutes .find the distance travelled?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #541038 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=541038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a rate * time = distance problem<BR>\n" );
document.write( "Let t1 be time to go from a to b and t2 be time to go from b to a, then<BR>\n" );
document.write( "4*t1 = 6*t2, also<BR>\n" );
document.write( "Note that 45 minutes is 3/4 hour or .75 hour, then<BR>\n" );
document.write( "t1 + t2 = .75<BR>\n" );
document.write( "Solve for t1<BR>\n" );
document.write( "t1 = .75 - t2<BR>\n" );
document.write( "Substitute for t1 in first equation<BR>\n" );
document.write( "4*(.75 - t2) = 6*t2<BR>\n" );
document.write( "3 -4t2 = 6t2<BR>\n" );
document.write( "10t2 = 3<BR>\n" );
document.write( "Note that 3 hours is 180 minutes<BR>\n" );
document.write( "10t2 = 180<BR>\n" );
document.write( "t2 = 18<BR>\n" );
document.write( "t1 = 45 -18 = 27 minutes<BR>\n" );
document.write( "Now distance from a to b is 4*27/60 = 27/15 = 9/5 = 1.8 km<BR>\n" );
document.write( "Total distance is 2 * 1.8 = 3.6 km<BR>\n" );
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