document.write( "Question 893016: 1. The sum of the ages of a mother and a daughter is 50yrs. Five years ago, the mother’s age was 7 times the age of the daughter. The present ages of mother and daughter are in year \n" ); document.write( "
Algebra.Com's Answer #541003 by algebrahouse.com(1659)\"\" \"About 
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x = daughter's age now
\n" ); document.write( "50 - x = mother's age now {sum of ages is 50}\r
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\n" ); document.write( "\n" ); document.write( "x - 5 = daughter's age five years ago {subtracted 5 from age now}
\n" ); document.write( "45 - x = mother's age five years ago {subtracted 5 from age now}\r
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\n" ); document.write( "\n" ); document.write( "45 - x = 7(x - 5) {five years ago the mother was equal to 7 times the daughter}
\n" ); document.write( "45 - x = 7x - 35 {used distributive property}
\n" ); document.write( "80 = 8x {added 35 and added x to each side}
\n" ); document.write( "x = 10 {divided each side by 8}
\n" ); document.write( "50 - x = 40 {substituted 10, in for x, into 50 - x}\r
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\n" ); document.write( "\n" ); document.write( "daughter is 10
\n" ); document.write( "mother is 40
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