document.write( "Question 892777: The distribution of weekly salaries at a large company is reverse J-shaped with a mean of $1000 and a standard deviation of $370. What is the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75? \n" ); document.write( "

Algebra.Com's Answer #540999 by stanbon(75887) $\"\"$ $\"About$

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The distribution of weekly salaries at a large company is reverse J-shaped with a mean of $1000 and a standard deviation of $370. What is the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75?
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\n" ); document.write( "n = [z*s/E]^2
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\n" ); document.write( "80 = [z*370/75]^2
\n" ); document.write( "----
\n" ); document.write( "sqrt(80) = 4.93z
\n" ); document.write( "z = 1.81
\n" ); document.write( "------
\n" ); document.write( "P(z > 1.81) = 0.035
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\n" ); document.write( "Ans:: P(condition described) = 2*0.035) = 7%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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