document.write( "Question 75324This question is from textbook Alegbra 2 An Incremental Development
\n" ); document.write( ": PLease help to simplify : \r
\n" ); document.write( "\n" ); document.write( "-3i^4 + 5i^3\r
\n" ); document.write( "\n" ); document.write( "Divided by\r
\n" ); document.write( "\n" ); document.write( "6i^2 - 7i
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Algebra.Com's Answer #54097 by scott8148(6628)\"\" \"About 
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eliminate the i's from the denominator by multiplying the numerator and denominator by \"6i%5E2%2B7i\"\r
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\n" ); document.write( "\n" ); document.write( "FOILing the two pairs of binomials gives \"%28-18i%5E6%2B30i%5E5%2B21i%5E5-35i%5E4%29%2F%2836i%5E4%2B49i%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "simplifying gives \"%2851i%5E3%2B17%29%2F13\"
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