document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892364>Question 892364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove : Two numbers when divided by a certain divisior give remainders r1 and r2. When their sum is divided by the same divisor, the remainder is r3. The divisor is given by r1 + r2 - r3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540958 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540958\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is not always true. Suppose our divisor is 10 and the two numbers are 11 and 21. Then r1, r2 = 1, 1 and r3 = 2. The divisor is not 1 + 1 - 2 = 0.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "However, it is true that r1 + r2 - r3 is a multiple of the divisor. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );