document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892532>Question 892532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sn problem; above greek symbol is k on the bottom is n=0. Directly next to it is n^2=(k(k+1)(2k+1))/6 check that its correct for k=1,2, and 3.\r<BR>\n" );
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document.write( "B.) Use the same formula to compute the value of m=0 top 5 (2m^3+3m-4)\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540957 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That's the Greek letter sigma, btw. For example:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large \sum_{n=0}^k n^2 = \frac{k(k+1)(2k+1)}{6}\">\r<BR>\n" );
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document.write( "If k = 3, then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\large \sum_{n=0}^3 n^2 = 0^3 + 1^2 + 2^2 + 3^2 = 14 = \frac{3(4)(7)}{6}\"> which is a true statement.\r<BR>\n" );
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document.write( "Basically, just replace the index (in the above case, n) with its starting value and increment until you get to the top number, and add everything up. </SPAN>\n" );
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