document.write( "Question 892917: Consider all four-digit numbers that can be formed each time taking the 4 digits of 2014. Without repeating any digit, what is the sum?? \n" ); document.write( "
Algebra.Com's Answer #540907 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "In thes problems always choose the most restrictive things first.\r\n" );
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document.write( "We can't choose the first digit as 0, so it's the mosty restrictive.\r\n" );
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document.write( "We can choose the first digit 3 ways {2,1,4}\r\n" );
document.write( "We can choose the second digit as any of the 3 remaining ways. (it can be 0).\r\n" );
document.write( "We can choose the second digit either of the 2 remaining ways.\r\n" );
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document.write( "That's 3*3*2 = 18 ways.\r\n" );
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document.write( "Here are all 18 ways:\r\n" );
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document.write( " 1. 1024\r\n" );
document.write( " 2. 1042\r\n" );
document.write( " 3. 1204\r\n" );
document.write( " 4. 1240\r\n" );
document.write( " 5. 1402\r\n" );
document.write( " 6. 1420\r\n" );
document.write( " 7. 2014\r\n" );
document.write( " 8. 2041\r\n" );
document.write( " 9. 2104\r\n" );
document.write( "10. 2140\r\n" );
document.write( "11. 2401\r\n" );
document.write( "12. 2410\r\n" );
document.write( "13. 4012\r\n" );
document.write( "14. 4021\r\n" );
document.write( "15. 4102\r\n" );
document.write( "16. 4120\r\n" );
document.write( "17. 4201\r\n" );
document.write( "18. 4210\r\n" );
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document.write( "Edwin
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