document.write( "Question 892849: Two consecutive even integers such that three times the smaller one exceeds two times the larger one by 7 \n" ); document.write( "
Algebra.Com's Answer #540881 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
3*2n=2*(2n+2)+7
\n" ); document.write( "6n=4n+4+7
\n" ); document.write( "2n=11
\n" ); document.write( "2n+2=13
\n" ); document.write( "The numbers are 11 and 13
\n" ); document.write( "But they are not even.
\n" ); document.write( "check
\n" ); document.write( "3*11=2*13+7
\n" ); document.write( "33=26+7
\n" ); document.write( "33=33
\n" ); document.write( "ok
\n" ); document.write( "There was no need in this case to use 2n and 2n+2
\n" ); document.write( "n and n+2 will do nicely\r
\n" ); document.write( "\n" ); document.write( "3*n=2(n+2)+7
\n" ); document.write( "3n=2n+4+7
\n" ); document.write( "n=11
\n" ); document.write( "n+2=13\r
\n" ); document.write( "\n" ); document.write( "unfortunately the answers are odd and even answers don't exist\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );