document.write( "Question 892902: Jack invests $2,000 at a certain annual interest rate, and he invests another $3,000 at an annual rate that is one-half percent higher. If he receives a total of $265 interest in one year, at what rate is the $2,000 invested? \n" ); document.write( "
Algebra.Com's Answer #540875 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"2000%2A%281%2Br%29-2000%2B3000%2A%281%2Br%2B0.005%29-3000=265\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The rate, r, is in the form of a decimal fraction.
\n" ); document.write( "1% would be 0.01, and then (1/2)% would be half of 0.01, meaning 0.005.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solving the equation:
\n" ); document.write( "The equation can be put into simpler form,
\n" ); document.write( "\"2000%2Ar%2B3000%2A%28r%2B0.005%29=265\", just focusing on the interest.
\n" ); document.write( "\"2000r%2B3000r%2B3%2A5%2A1000%2A%280.001%29=265\"
\n" ); document.write( "\"5000r%2B15=265\"
\n" ); document.write( "\"5000r=250\"
\n" ); document.write( "\"r=250%2F5000\"
\n" ); document.write( "\"r=25%2F500\"
\n" ); document.write( "\"r=5%2F100\"
\n" ); document.write( "r=5%
\n" ); document.write( "
\n" );