document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75365>Question 75365</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee merchant has coffee beens that sell for $9 p/lb & $12 p/lb. the two types are mixed to to create 100 lb of a mixture to sell for $11.25 p/lb. How much of each type of bean should be used in the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54083 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 100*11.25=x*12+(100-x)9<BR>\n" );
document.write( "1125=12x+900-9x<BR>\n" );
document.write( "12x-9x=1125-900<BR>\n" );
document.write( "3x=225<BR>\n" );
document.write( "x=225/3<BR>\n" );
document.write( "x=75 pounds of $12 coffee.<BR>\n" );
document.write( "100-75=25 pounds of $9 coffee.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "100*11.25=75*12+25*9<BR>\n" );
document.write( "1125=900+225<BR>\n" );
document.write( "1125=1125<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );