document.write( "Question 892835: Write x^2-6x+7=0 in the form (x-a)^2=b! where a and b are intergers \n" ); document.write( "
Algebra.Com's Answer #540822 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"x%5E2-6x%2B7\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "\"x%5E2-6x\"\"%22%22=%22%22\"\"-7\"\r\n" );
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document.write( "Multiply \"-6\" by \"1%2F2\", get \"-3\"\r\n" );
document.write( "Square \"-3\" get \"%28-3%29%5E2=%22%22+%2B+9\".\r\n" );
document.write( "Add \"%22%22%2B9\" to both sides:\r\n" );
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document.write( "\"x%5E2-6x%2B9\"\"%22%22=%22%22\"\"-7%2B9\"\r\n" );
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document.write( "Factor the left side, combine terms on right:\r\n" );
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document.write( "\"%28x-3%29%28x-3%29\"\"%22%22=%22%22\"\"2\"\r\n" );
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document.write( "Both factors are the same, so write as one of them squared.\r\n" );
document.write( "Since 2 = 2!, write 2 that way:\r\n" );
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document.write( "\"%28x-3%29%5E2\"\"%22%22=%22%22\"\"2%21\"\r\n" );
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document.write( "That's in the form \"%28x-a%29%5E2\"\"%22%22=%22%22\"\"b%21\", where\r\n" );
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document.write( "a and b are the integers 3 and 2 respetively, and 2 is written as\r\n" );
document.write( "a factorial 2!.\r\n" );
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document.write( "Edwin
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