document.write( "Question 892744: This is a cost-revenue word problem. I tried using the form C=Rx+b which just confused me more. A rental company offers two plans. Plan I offers $10 a day and 10 cents a mile, while Plan II charges 14 cents a day, but no flat fee. If you were to drive 300 miles a day, which plan is better? For what mileage are both rates equal? \n" ); document.write( "
Algebra.Com's Answer #540807 by Theo(13342)![]() ![]() You can put this solution on YOUR website! plan 1 costs 10 dollars a day plus 10 cents a mile.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for plan 1 is c = .10 * 300 + 10 = 40 dollars.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plan 2 costs 0 dollars a day plus 14 cents a mile.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for plan 2 is c = .14 * 300 = 42 dollars.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plan 1 is cheaper because the total cost for plan 1 is 40 dollars while the total cost for plan 2 is 42 dollars.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula c = rx + b works but you have to be careful what gets assigned to what.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for plan 1, r = .10 and x = 300 and b = 10 \n" ); document.write( "for plan 2, r = .14 and x = 300 and b = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "note that if you had rented for more than a day, the formula would have had to have been c = rx + by \n" ); document.write( "r would be the cost per mile. \n" ); document.write( "x would be the number of miles. \n" ); document.write( "b would be the cost per day. \n" ); document.write( "y would be the number of days.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |