document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892765>Question 892765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a security light is being installed outside a loading dock.  the light must be placed at a 52 degree angle so that it illluminates a parking lot.  if the distance from the end of the parking lot to the loading dock is 100 feet, what is the height of the security light.?\r<BR>\n" );
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document.write( "am I using tangent to solve?  not sure what to do. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540774 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the 52 degrees is between the wall and direction the light is pointing,<BR>\n" );
document.write( "then the 100 feet is opposite from the 52 degree angle, and<BR>\n" );
document.write( "the height of the light is the adjacent side of the triangle.<BR>\n" );
document.write( "so tan(52) = opposite/adjacent = 100/adjacent<BR>\n" );
document.write( "let x = the length of the adjacent side<BR>\n" );
document.write( " tan(52) = 100/x<BR>\n" );
document.write( "x*tan(52) = 100<BR>\n" );
document.write( "divide each side by tan(52)<BR>\n" );
document.write( "x = 100/tan(52)<BR>\n" );
document.write( "x = 78.128 feet<BR>\n" );
document.write( "If the 52 degrees is from horizontal, the angle of interest is 90-52 = 38 degrees<BR>\n" );
document.write( "we would want to solve tan(38) = 100/x<BR>\n" );
document.write( "and x = 100/tan(38) = 128 feet<BR>\n" );
document.write( "In either case it seems unlikely we would expect to place a light that high. </SPAN>\n" );
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