document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75370>Question 75370</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 84 cm.  the length is twice the width.  Find the length and width.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54073 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2l+2w=perimeter<BR>\n" );
document.write( "2*2w+2w=84<BR>\n" );
document.write( "4w+2w=84<BR>\n" );
document.write( "6w=84<BR>\n" );
document.write( "w=84/6<BR>\n" );
document.write( "w=14 solution for the width.<BR>\n" );
document.write( "2*14=28 for the length.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "2*28+2*14=84<BR>\n" );
document.write( "56+28=84<BR>\n" );
document.write( "84=84\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );