document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892655>Question 892655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A scale is accurate within .5 pound how do I write an absolute value inequality if a person weighs 95 pounds to express the possible error in the weight (w) given by the scale. I then have to solve the inequality </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540724 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe your solution is going to be:\r<BR>\n" );
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document.write( "|x - 95| <= .5\r<BR>\n" );
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document.write( "x represents the weight of the person as measured by the scale.\r<BR>\n" );
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document.write( "here's how it works.\r<BR>\n" );
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document.write( "suppose the person weighs 95.5 pounds.\r<BR>\n" );
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document.write( "equation becomes |95.5 - 95| <= .5 which becomes |.5| <= .5 which becomes .5 <= .5 which is within the prescribed limits.\r<BR>\n" );
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document.write( "suppose the person weighs 94.5 pounds.\r<BR>\n" );
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document.write( "equation becomes |94.5 - 95| <= .5 which becomes |-.5| <= .5 which becomes .5 <= .5 which is also good.\r<BR>\n" );
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document.write( "since the maximum error of the scale is +/- .5, the scale will not measure a 95 pound person outside those limits.\r<BR>\n" );
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document.write( "you can expect that |x - 95| <= .5\r<BR>\n" );
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document.write( "suppose the scale measures 94.8 pounds.\r<BR>\n" );
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document.write( "the difference is -.2 which becomes .2 which is less than .5.\r<BR>\n" );
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document.write( "suppose the scale measures 95.2 pounds.\r<BR>\n" );
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document.write( "the difference is +.2 which becomes .2 which is less than .5.\r<BR>\n" );
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document.write( "the absolute value automtically takes care of the plus and minus aspects of the difference.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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