document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892698>Question 892698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve this? Area = 1/2 (6&#8730;2)(2&#8730;20)\r<BR>\n" );
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document.write( "thanks I got confuse. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540721 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540721\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area of a triangle is equal to 1/2 * base * height\r<BR>\n" );
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document.write( "it appears that the base is equal to 6*sqrt(2) and that the height is equal to 2*sqrt(20), or vice versa.   it doesn't matter which is which because you are multiplying everything together anyway.\r<BR>\n" );
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document.write( "your formula is area = 1/2 * 6*sqrt(2) * 2*sqrt(20)\r<BR>\n" );
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document.write( "you can use the commutative law of multiplication to make your formula look like this:\r<BR>\n" );
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document.write( "area = 1/2 * 6 * 2 * sqrt(2) * sqrt(20)\r<BR>\n" );
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document.write( "you can use the associative law of multiplication to make your formula look like this:\r<BR>\n" );
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document.write( "area = (1/2) * (6*2) * (sqrt(2)*sqrt(20))\r<BR>\n" );
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document.write( "the square root laws allow you to make sqrt(2)*sqrt(20) equal to sqrt(2*20)\r<BR>\n" );
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document.write( "your equation becomes:\r<BR>\n" );
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document.write( "area = (1/2) * (6*2) * sqrt(2*20)\r<BR>\n" );
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document.write( "simplify this to get:\r<BR>\n" );
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document.write( "area = (1/2) * 12 * sqrt(40)\r<BR>\n" );
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document.write( "use the associative law again to make your equation look like this:\r<BR>\n" );
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document.write( "area = ((1/2)*12) * sqrt(40)\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "area = 6 * sqrt(40)\r<BR>\n" );
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document.write( "sqrt(40) is equal to sqrt(4*10) which is equal to 2*sqrt(10).\r<BR>\n" );
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document.write( "your equation becomes:\r<BR>\n" );
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document.write( "area = 6*2*sqrt(10)\r<BR>\n" );
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document.write( "simplify this to get area = 12*sqrt(10)\r<BR>\n" );
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document.write( "it can't be simplified any further than that since there are no perfect squares in sqrt(10).\r<BR>\n" );
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document.write( "your original equation was area = (1/2) * 6 * sqrt(2) * 2 * sqrt(20)\r<BR>\n" );
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document.write( "your final equation is area = 12 * sqrt(10).\r<BR>\n" );
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document.write( "if you simplified correctly, they should get you the same answer.\r<BR>\n" );
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document.write( "now you use your calculator to confirm that both equations will give you the same answer.\r<BR>\n" );
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document.write( "i did the calculations and confirmed that both equations give you the same answer.\r<BR>\n" );
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document.write( "the answer that both equations gave me is 37.94733192.\r<BR>\n" );
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document.write( "i'm not exactly sure what you were asked to do.\r<BR>\n" );
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document.write( "if you just needed an answer, you could have solved it directly using the calculator and gotten 37.94733192.\r<BR>\n" );
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document.write( "if you were asked to simplify the equation, then your simplified equation is area = 12*sqrt(10).\r<BR>\n" );
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document.write( " </SPAN>\n" );
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