document.write( "Question 892645: The width of a rectangle is 5 cm less than half it length. Its area is 72 cm squared. Find the length and the width of the rectangle \n" ); document.write( "

Algebra.Com's Answer #540694 by josgarithmetic(39618) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"w=-5%2B2L\"$ and $\"wL=72\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"%282L-5%29L=72\"$
\n" ); document.write( " $\"2L%5E2-5L-72=0\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"L=%285%2B-+sqrt%2825%2B4%2A2%2A72%29%29%2F4\"$
\n" ); document.write( " $\"L=%285%2B-+sqrt%281800%29%29%2F4\"$
\n" ); document.write( " $\"L=%285%2B-+10sqrt%282%2A3%2A3%29%29%2F4\"$
\n" ); document.write( " $\"L=%285%2B-+30sqrt%282%29%29%2F4\"$ , choose the PLUS form.
\n" ); document.write( " $\"highlight%28L=%285%2B30sqrt%282%29%29%2F4%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Just use the earlier described formula for w to find its value from L.
\n" ); document.write( "You can use either initially described formulas, including wL=72 if you want.
\n" ); document.write( " $\"w=72%2FL\"$ . If do that,
\n" ); document.write( " $\"w=72%2F%28%285%2B30sqrt%282%29%29%2F4%29\"$
\n" ); document.write( " $\"w=%2872%2A4%29%2F%285%2B30sqrt%282%29%29\"$ , and should rationalize the denominator.
\n" ); document.write( " $\"w=%2872%2A4%285-30sqrt%282%29%29%29%2F%2825-900%2A2%29\"$
\n" ); document.write( " $\"w=%2872%2A4%2830sqrt%282%29-5%29%29%2F%281800-25%29\"$
\n" ); document.write( " $\"w=%2872%2A4%2A5%286sqrt%282%29-1%29%29%2F1775\"$
\n" ); document.write( " $\"w=%2872%2A4%286sqrt%282%29-1%29%29%2F355\"$
\n" ); document.write( " $\"highlight%28w=%28288%2F355%29%286sqrt%282%29-1%29%29\"$ ----maybe the linear form would have been easier. Should have used $\"2L-5\"$ instead. \n" ); document.write( "

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