document.write( "Question 75236: If 10% of the rivets produced by a machine are defective, find the probability that out of 5 randomly chosen rivets:
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document.write( "(i) one or more will be defective
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document.write( "(ii)at most two will be defective\r
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document.write( "It would be really helpful for me if you could answer this question. Thank you. \n" );
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Algebra.Com's Answer #54069 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If 10% of the rivets produced by a machine are defective, find the probability that out of 5 randomly chosen rivets: \n" ); document.write( "The problem is \"binomial\" because the rivets are defective or not defective. \n" ); document.write( "P(defective)=0.10; P(not defective)=0.90 \n" ); document.write( "(i) P(one or more will be defective) = 1 - P(none are defective) \n" ); document.write( "1-(0.90)^5 \n" ); document.write( "= 0.40951 \n" ); document.write( "----------- \n" ); document.write( "If you use a TI calculator it is \"1 - binompdf(5,0.1,0)\" \n" ); document.write( "========================\r \n" ); document.write( "\n" ); document.write( "(ii)P(at most two will be defective) \n" ); document.write( "=P(x=0)+P(x=1)+P(x=2) \n" ); document.write( "=binomcdf(5,0.1,2)=0.99144 \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |