document.write( "Question 892171: 2 sin^2x+sinx=1
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document.write( "Find all solutions to each equation for 0 less than or equal too x which is less than or equal to 2pi \n" );
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Algebra.Com's Answer #540674 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2 sin^2x+sinx=1 \n" ); document.write( "Find all solutions to each equation for 0<= x <=2pi \n" ); document.write( "--------------- \n" ); document.write( "2sin^2(x) + sin(x) -1 = 0 \n" ); document.write( "------ \n" ); document.write( "Use the quadratic formula to get: \n" ); document.write( "sin(x) = [-1 +- sqrt(1-4*2*-1)]/4 \n" ); document.write( "---- \n" ); document.write( "sin(x) = [-1 +- sqrt(9)]/4 \n" ); document.write( "---- \n" ); document.write( "sin(x) = [-1 +- 3]/4 \n" ); document.write( "--- \n" ); document.write( "sin(x) = 1/2 or sin(x) = -1 \n" ); document.write( "----- \n" ); document.write( "If sin(x) = 1/2, x = pi/6 or (5/6)pi \n" ); document.write( "If sin(x) = -1, x = (3/2)pi \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------------- \n" ); document.write( " \n" ); document.write( " |