document.write( "Question 892641: A substance decays exponentially. If the 80 ounces of the substance decays to 9 ounces in 3 hours. What is the half - life of the substance? \n" ); document.write( "
Algebra.Com's Answer #540673 by josgarithmetic(39617)\"\" \"About 
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\"p=Ie%5E%28-kt%29\", generalized exponential decay equation
\n" ); document.write( "p, how much present at time t starting from initial amount I
\n" ); document.write( "I, initial amount when t=0
\n" ); document.write( "t, time
\n" ); document.write( "k, a constant
\n" ); document.write( "e, the Euler number, base of Natural logarithm\r
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\n" ); document.write( "\n" ); document.write( "First, find k using I=80, p=9, t=3.
\n" ); document.write( "\"ln%28p%29=ln%28Ie%5E%28-kt%29%29\"
\n" ); document.write( "\"ln%28I%29%2Bln%28e%5E%28-kt%29%29=ln%28p%29\"
\n" ); document.write( "\"ln%28I%29%2B%28-k%29t%2A1=ln%28p%29\"
\n" ); document.write( "\"-kt=ln%28p%29-ln%28I%29\"
\n" ); document.write( "\"k=-%281%2Ft%29%28ln%28p%29-ln%28I%29%29\"
\n" ); document.write( "\"highlight%28k=-%281%2Ft%29%28ln%28p%2FI%29%29%29\"
\n" ); document.write( "For the value of k:
\n" ); document.write( "\"k=-%281%2F3%29%28ln%289%2F80%29%29\"
\n" ); document.write( "\"highlight%28k=0.728%29\", using k as a positive value.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Half-Life
\n" ); document.write( "Here, \"p=I%2F2\".
\n" ); document.write( "\"p=I%2F2=Ie%5E%28-0.728%2At%29\"
\n" ); document.write( "\"1%2F2=e%5E%28-0.728t%29\"
\n" ); document.write( "\"ln%281%2F2%29=-0.728t%2A1\"
\n" ); document.write( "\"t=-1%2F%280.728%29ln%281%2F2%29\"
\n" ); document.write( "\"highlight%28t=0.952%29\" in hours.
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