document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892635>Question 892635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve. (-1/64)^2/3<BR>\n" );
document.write( "I tried 6 times over and over and am frustrated. It is the only question I doin't know to finish this test please help thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540662 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since by order of operation, exponents are evaluated first,<BR>\n" );
document.write( "(-1/64)^2/3 is the same as ((-1/64)^2)/3<BR>\n" );
document.write( "(-1/64)^2 = 1/(64)^2 = 1/4096 so,<BR>\n" );
document.write( "(-1/64)^2/3 = (1/4096)/3 = 1/(3*4096) = 1/12288 </SPAN>\n" );
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