document.write( "Question 892570: its a family of three the husband is 5years older than the wife and the son is half his mothers age ...altogether they sum up to 100. Question:: how ald is da husband ,,wife. And son !?!? Added together da answer must be hundred \n" ); document.write( "

Algebra.Com's Answer #540642 by Jynald-(6) $\"\"$ $\"About$

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let w be the wife's age,
\n" ); document.write( "5 + w be the age of husband
\n" ); document.write( "and w/2 be the age of their son\r
\n" ); document.write( "\n" ); document.write( "solve for age of wife
\n" ); document.write( "100 = (5+w) + w + w/2
\n" ); document.write( "100 = 5 + 2w + w/2
\n" ); document.write( "200 = 10 + 4w + w
\n" ); document.write( "200-10 = 5w
\n" ); document.write( "190/5 = 5w/5
\n" ); document.write( "38 = w\r
\n" ); document.write( "\n" ); document.write( "solve for son's age:
\n" ); document.write( "w/2
\n" ); document.write( "38/2 = 19\r
\n" ); document.write( "\n" ); document.write( "solve for husband's age:
\n" ); document.write( "5 + w
\n" ); document.write( "5 + 38 = 43\r
\n" ); document.write( "\n" ); document.write( "checking:
\n" ); document.write( "husband's age plus son's age plus wife's age equals 100
\n" ); document.write( "43 + 19 + 38 = 100
\n" ); document.write( "100 = 100 \n" ); document.write( "

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