document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892589>Question 892589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a certain rectangle is 3 meters more than twice its width. If the perimeter of the rectangle is 90 meters, then the width of the rectangle is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540637 by </B><A HREF=/tutors/aboutme.mpl?userid=Jynald-><B>Jynald-(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jynald-><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jynald-><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let w be the width<BR>\n" );
document.write( "and 3 + w be the length\r<BR>\n" );
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document.write( "2l + 2w = Perimeter<BR>\n" );
document.write( "2(3+w) + 2w = 90<BR>\n" );
document.write( "6 + 2w + 2w = 90<BR>\n" );
document.write( "4w = 90 - 6<BR>\n" );
document.write( "4w = 84<BR>\n" );
document.write( "4w/4 = 84/4<BR>\n" );
document.write( "w = 21 \r<BR>\n" );
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document.write( "solve for length<BR>\n" );
document.write( "3 + w<BR>\n" );
document.write( "3 + 21 = 24\r<BR>\n" );
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document.write( "checking:<BR>\n" );
document.write( "2(24) + 2(21) = 90<BR>\n" );
document.write( "48 + 42 = 90<BR>\n" );
document.write( "90 = 90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );