document.write( "Question 892608: The great circle has an area of 289pie square feet.
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Algebra.Com's Answer #540628 by jim_thompson5910(35256)\"\" \"About 
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A = pi*r^2\r
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\n" ); document.write( "\n" ); document.write( "289pi = pi*r^2\r
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\n" ); document.write( "\n" ); document.write( "289 = r^2\r
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\n" ); document.write( "\n" ); document.write( "r^2 = 289\r
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\n" ); document.write( "\n" ); document.write( "r = sqrt(289)\r
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\n" ); document.write( "\n" ); document.write( "r = 17\r
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\n" ); document.write( "\n" ); document.write( "The radius of this sphere is 17 feet.\r
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\n" ); document.write( "\n" ); document.write( "Surface Area:\r
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\n" ); document.write( "\n" ); document.write( "SA = 4pi*r^2\r
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\n" ); document.write( "\n" ); document.write( "SA = 4pi*17^2\r
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\n" ); document.write( "\n" ); document.write( "SA = 1156pi\r
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\n" ); document.write( "\n" ); document.write( "The exact surface area of this sphere is 1156pi\r
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\n" ); document.write( "\n" ); document.write( "Volume:\r
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\n" ); document.write( "\n" ); document.write( "V = (4/3)pi*r^3\r
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\n" ); document.write( "\n" ); document.write( "V = (4/3)pi*17^3\r
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\n" ); document.write( "\n" ); document.write( "V = (19652/3)pi\r
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\n" ); document.write( "\n" ); document.write( "The exact volume of this sphere is (19652/3)pi
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