document.write( "Question 892538: 2. a canoeist can paddle 2 miles up the pasig river in the same time he can paddle 6 miles downstream. the speed of the current is 2 mph. what is his speed in still water ? \n" ); document.write( "
Algebra.Com's Answer #540616 by ankor@dixie-net.com(22740)\"\" \"About 
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a canoeist can paddle 2 miles up the pasig river in the same time he can paddle 6 miles downstream.
\n" ); document.write( " the speed of the current is 2 mph. what is his speed in still water ?
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\n" ); document.write( "let s = his speed in still water
\n" ); document.write( "then
\n" ); document.write( "(s+2) = his effective speed downstream
\n" ); document.write( "and
\n" ); document.write( "(s-2) = his effective speed upstream
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( "\"6%2F%28%28s%2B2%29%29\" = \"2%2F%28%28s-2%29%29\"
\n" ); document.write( "cross multiply
\n" ); document.write( "6(s-2) = 2(s+2)
\n" ); document.write( "6s - 12 = 2s + 4
\n" ); document.write( "6s - 2s = 4 + 12
\n" ); document.write( " 4s = 16
\n" ); document.write( "s = 16/4
\n" ); document.write( "s = 4 mph speed in still water
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this find the time each way, using the effective speeds
\n" ); document.write( "6/6 = 1 hr
\n" ); document.write( "2/2 = 1 hr
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