document.write( "Question 892538: 2. a canoeist can paddle 2 miles up the pasig river in the same time he can paddle 6 miles downstream. the speed of the current is 2 mph. what is his speed in still water ? \n" ); document.write( "
Algebra.Com's Answer #540616 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a canoeist can paddle 2 miles up the pasig river in the same time he can paddle 6 miles downstream. \n" ); document.write( " the speed of the current is 2 mph. what is his speed in still water ? \n" ); document.write( ": \n" ); document.write( "let s = his speed in still water \n" ); document.write( "then \n" ); document.write( "(s+2) = his effective speed downstream \n" ); document.write( "and \n" ); document.write( "(s-2) = his effective speed upstream \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "6(s-2) = 2(s+2) \n" ); document.write( "6s - 12 = 2s + 4 \n" ); document.write( "6s - 2s = 4 + 12 \n" ); document.write( " 4s = 16 \n" ); document.write( "s = 16/4 \n" ); document.write( "s = 4 mph speed in still water \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this find the time each way, using the effective speeds \n" ); document.write( "6/6 = 1 hr \n" ); document.write( "2/2 = 1 hr \n" ); document.write( " |