document.write( "Question 892582: If the perimeter of a rectangle is p and its diagnoal is d, the difference between the length and width of the rectangle is ______?\r
\n" ); document.write( "\n" ); document.write( "I have worked several formulas, 2L Plus 2W = p, solved for L, and tryig to solve for W, I have worked it several ways. I have also used the Pathagoreum theorm, L squared plus w squared = d squared. I have not been able to solve it, begining to wonder if it is a trick problem from instructor. Can you help.
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Algebra.Com's Answer #540607 by josgarithmetic(39799)\"\" \"About 
You can put this solution on YOUR website!
This can only be done using variables because no values are given.\r
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\n" ); document.write( "\n" ); document.write( "\"p=2w%2B2L\" and \"w%5E2%2BL%5E2=d%5E2\";
\n" ); document.write( "You want to find \"abs%28w-L%29\".
\n" ); document.write( "You assume that the constants are d and p.\r
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\n" ); document.write( "\n" ); document.write( "\"2L=p-2w\"
\n" ); document.write( "\"L=%28p-2w%29%2F2\";
\n" ); document.write( "substitute into the diagonal equation.
\n" ); document.write( "\"w%5E2%2B%28p-2w%29%5E2%2F4=d%5E2\"
\n" ); document.write( "\"4w%5E2%2B%28p-2w%29%5E2=4d%5E2\"
\n" ); document.write( "\"4w%5E2%2Bp%5E2-4pw%2B4w%5E2-d%5E2=0\"
\n" ); document.write( "\"8w%5E2-4pw%2Bp%5E2-d%5E2=0\"
\n" ); document.write( "Use the general solution of quadratic equation.
\n" ); document.write( "\"w=%284p%2B-+sqrt%2816p%5E2-4%2A8%28p%5E2-d%5E2%29%29%29%2F%2816%29\"
\n" ); document.write( "\"w=%284p%2B-+sqrt%2816p%5E2-32%28p%5E2-d%5E2%29%29%29%2F16\"
\n" ); document.write( "\"w=%284p%2B-+4sqrt%28p%5E2-2%28p%5E2-d%5E2%29%29%2F16\"
\n" ); document.write( "\"w=%28p%2B-+sqrt%28p%5E2-2p%5E2%2B2d%5E2%29%29%2F4\"
\n" ); document.write( "\"highlight_green%28w=%28p%2B-+sqrt%282d%5E2-p%5E2%29%29%2F4%29\"-----this is just for w.\r
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\n" ); document.write( "\n" ); document.write( "What about the other dimension, L?
\n" ); document.write( "... w=(p-2L)/2;
\n" ); document.write( "\"%28p-2L%29%5E2%2F4%2BL%5E2=d%5E2\" when substituted into the diagonal equation.
\n" ); document.write( "\"%28p-2L%29%5E2%2B4L%5E2=4d%5E2\"
\n" ); document.write( "\"p%5E2-4pL%2B4L%5E2%2B4L%5E2=d%5E2\"
\n" ); document.write( "\"p%5E2-4pL%2B8L%5E2-d%5E2=0\"
\n" ); document.write( "\"8L%5E2-4pL%2Bp%5E2-d%5E2=0\"
\n" ); document.write( "General Solution,
\n" ); document.write( "\"L=%284p%2B-+sqrt%2816p%5E2-4%2A8%28p%5E2-d%5E2%29%29%29%2F16\"
\n" ); document.write( "\"L=%284p%2B-+sqrt%2816p%5E2-16%2A2%28p%5E2-d%5E2%29%29%29%2F16\"
\n" ); document.write( "\"L=%284p%2B-+4sqrt%28p%5E2-2%28p%5E2-d%5E2%29%29%2F16\"
\n" ); document.write( "\"L=%28p%2B-+sqrt%28p%5E2-2p%5E2%2B2d%5E2%29%29%2F4\"
\n" ); document.write( "\"highlight_green%28L=%28p%2B-+sqrt%282d%5E2-p%5E2%29%29%2F4%29\"-----formula for L.\r
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\n" ); document.write( "\n" ); document.write( "YOU can finish this.
\n" ); document.write( "Pay attention to both forms for w and L, since each has a PLUS form and a MINUS form. Remember, you are looking for THE DIFFERENCE or absolute value of w and L.\r
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\n" ); document.write( "\n" ); document.write( "Please excuse the lack of rendering in three of the steps. Tracing the parentheses will be difficult. The majority of readable steps should be plenty helpful.
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