document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892564>Question 892564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is x years old and his daughter is y years old. three times the difference in their ages is 57. In 2 years time the father will be twice as old as the daughter. How old are they now? I can't work out what the equation would be to work this out. I thought x-y=57/3 which is the age difference but beyond that I do not know how to approach this question. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540598 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  3*(f-d)=57<BR>\n" );
document.write( "f-d=19<BR>\n" );
document.write( "f=d+19<BR>\n" );
document.write( "f+2=2*(d+2)<BR>\n" );
document.write( "f+2=2d+4<BR>\n" );
document.write( "f=2d+2<BR>\n" );
document.write( "d+19=2d+2<BR>\n" );
document.write( "17=d<BR>\n" );
document.write( "f=36\r<BR>\n" );
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