document.write( "Question 892571: Find the next two
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\n" ); document.write( "100, 25, 50, 12.5, 25,
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Algebra.Com's Answer #540593 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
One series could be
\n" ); document.write( "A(n+1)=An*1/4 then A(n+2)=A(n+1)*2\r
\n" ); document.write( "\n" ); document.write( "100*1/4=25
\n" ); document.write( "25*2=50
\n" ); document.write( "50*1/4=12.5
\n" ); document.write( "12.5*2=25
\n" ); document.write( "25*1/4=6.25
\n" ); document.write( "6.25*2=12.5\r
\n" ); document.write( "\n" ); document.write( "so the next two could be
\n" ); document.write( "6.25 and 12.5\r
\n" ); document.write( "\n" ); document.write( "Another possibility
\n" ); document.write( "100 -75 100 -162.5 275
\n" ); document.write( "25 25 -62.5 112.5 275
\n" ); document.write( "50 -37.5 50 387.5
\n" ); document.write( "12.5 12.5 437.5
\n" ); document.write( "25 450.0
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\n" ); document.write( "The sixth term could be 475\r
\n" ); document.write( "\n" ); document.write( "100 -75 100 -162.5 275 0
\n" ); document.write( "25 25 -62.5 112.5 275 0
\n" ); document.write( "50 -37.5 50 387.5 275
\n" ); document.write( "12.5 12.5 437.5 662.5
\n" ); document.write( "25 450 1100
\n" ); document.write( "475 1550
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\n" ); document.write( "7th term could be 2025
\n" ); document.write( "so the 6th and 7th terms could be 475 and 2025\r
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