document.write( "Question 75341: Consider the following frequency table of the performance ratings on a scale of 1–good, 2–fair, and 3–poor, bestowed on their local baseball team by a collection of 100 fans:\r
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\n" ); document.write( "1 20\r
\n" ); document.write( "\n" ); document.write( "2 30\r
\n" ); document.write( "\n" ); document.write( "3 50
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\n" ); document.write( "\n" ); document.write( " The cumulative relative frequencies for each performance rating are\r
\n" ); document.write( "\n" ); document.write( " a. 1–20%, 2–30%, 3–50% \r
\n" ); document.write( "\n" ); document.write( " b. 1–20%, 2–50%, 3–100%\r
\n" ); document.write( "\n" ); document.write( " c. 1–80%, 2–70%, 3–50%\r
\n" ); document.write( "\n" ); document.write( " d. 1–50%, 2–30%, 3–20%\r
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\n" ); document.write( "\n" ); document.write( "Thank You
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Algebra.Com's Answer #54055 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Relative frequencies are gotten when you divide each class frequency
\n" ); document.write( "by the sum of the frequencies.
\n" ); document.write( "In your problem the sum is 100; so freq=20 means relative freq of 20/100=20%
\n" ); document.write( "The same for freq 30; rel freq is 30/100 = 30%
\n" ); document.write( "The same for freq 50; rel freq is 50/100=50%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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