document.write( "Question 892474: the vertices of the base of an isosceles triangle are at (1,2) and (4,-1). If the abscissa of the third vertex is 6, find its ordinate.\r
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Algebra.Com's Answer #540532 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
You want your unknown point (6,y) to be the same distance from (1,2) as it is from (4,-1).
\n" ); document.write( "The segments, (6,y) to (1,2), and (6,y) to (4,-1), are the two equal sides of the isosceles
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\n" ); document.write( "\n" ); document.write( " $\"sqrt%28%286-1%29%5E2%2B%28y-2%29%5E2%29=sqrt%28%286-4%29%5E2%2B%28y-%28-1%29%29%5E2%29\"$
\n" ); document.write( " $\"sqrt%28%285%29%5E2%2B%28y-2%29%5E2%29=sqrt%28%282%29%5E2%2B%28y%2B1%29%5E2%29\"$
\n" ); document.write( " $\"sqrt%2825%2B%28y-2%29%5E2%29=sqrt%284%2B%28y%2B1%29%5E2%29\"$
\n" ); document.write( " $\"%28y-2%29%5E2%2B25=%28y%2B1%29%5E2%2B4\"$
\n" ); document.write( " $\"y%5E2-4y%2B4%2B25=y%5E2%2B2y%2B1%2B4\"$ , see $\"y%5E2\"$ on both sides
\n" ); document.write( " $\"-4y%2B29=2y%2B5\"$
\n" ); document.write( " $\"-6y%2B29=5\"$
\n" ); document.write( " $\"-6y=5-29\"$
\n" ); document.write( " $\"6y=29-5\"$
\n" ); document.write( " $\"6y=24\"$
\n" ); document.write( " $\"highlight%28y=4%29\"$ --------the ordinate, or y value for the vertex opposite of the base.\r
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