document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892478>Question 892478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 88 inches. if the length of the rectangle is 8 inches more than 3 times the width, find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540519 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w = width<BR>\n" );
document.write( "3w + 8 = length  {lenght is 8 more than 3 times width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r<BR>\n" );
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document.write( "2w + 2(3w + 8) = 88 {substituted into perimeter formula}<BR>\n" );
document.write( "2w + 6w + 16 = 88 {used distributive property}<BR>\n" );
document.write( "8w + 16 = 88 {combined like terms}<BR>\n" );
document.write( "8w = 72 {subtracted 16 from each side}<BR>\n" );
document.write( "w = 9 {divided each side by 8}<BR>\n" );
document.write( "3w + 8 = 35 {substituted 9, in for w, into 3w + 8}\r<BR>\n" );
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document.write( "width = 9 inches<BR>\n" );
document.write( "length = 35 inches<BR>\n" );
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