document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892464>Question 892464</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Is there anyone available that could assist me please<BR>\n" );
document.write( "You want to determine how many bunches of radishes you want to buy each day.  Here's what you know.\r<BR>\n" );
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document.write( "1.  You sell radishes (the sale price)  for a dollar a bunch.<BR>\n" );
document.write( "2.  You purchase radishes (the cost price) for 50 cents a bunch to sell<BR>\n" );
document.write( "3.  A farmer will purchase the old radishes for a dime a bunch to grind up for his farm animals.<BR>\n" );
document.write( "4.  You sell about 20 bunches a day.<BR>\n" );
document.write( "5.  The standard deviation (that give and take of how many you sell every day...some days 17, some days 25, some days 19) is 3. \r<BR>\n" );
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document.write( "So, you'll want to know based on the above, how many bunches your next order should be. (50 points).\r<BR>\n" );
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document.write( "First, find the cost per unit  or sale price minus cost price = C(u)\r<BR>\n" );
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document.write( "Second, find the difference of the cost price minus the price the famer will pay = C(o)\r<BR>\n" );
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document.write( "Third, find the purchase requirements by doing these steps:\r<BR>\n" );
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document.write( "a.  C(u)/C(o) +C(u) = P (only go out to four decimal places) (HINT:  This must be less than one - if it's greater than one - you've got the division wrong...if you are banging your head against the wall...it's time to call Dr. Fenner)\r<BR>\n" );
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document.write( "b.  go to this calculator to find the normsinv (probability value) (http://easycalculation.com/statistics/inverse-cumulative-normal-standard-distribution.php). Put the number you got for a. (probability) in the top box, hit calculate and then a number will appear in the normsinv (remember this number)\r<BR>\n" );
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document.write( "c.  Then calculate the purchase by:  number of bunches you sell now (number 4 above) plus Probability Value (the normsinv number from b. above) times your standard deviation (number 5 above) or\r<BR>\n" );
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document.write( "Sales + (Probability Value (the normsinv number) times Standard Deviation)\r<BR>\n" );
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document.write( "(Hint:  notice the distribution:  calculate Probability Value x Standard Deviation and then add this number to current sales)\r<BR>\n" );
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document.write( "HINT:  Watch your decimal places!\r<BR>\n" );
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document.write( "Show the math all along the way. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540512 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You want to determine how many bunches of radishes you want to buy each day. Here's what you know.<BR>\n" );
document.write( " 1. You sell radishes (the sale price) for a 100 cents a bunch.<BR>\n" );
document.write( " 2. You purchase radishes (the cost price) for 50 cents a bunch to sell<BR>\n" );
document.write( " 3. A farmer will purchase the old radishes for 10 cents a bunch to grind up for his farm animals.<BR>\n" );
document.write( " 4. You sell about 20 bunches a day.<BR>\n" );
document.write( " 5. The standard deviation (that give and take of how many you sell every day...some days 17, some days 25, some days 19) is 3.<BR>\n" );
document.write( " So, you'll want to know based on the above, how many bunches your next order should be. (50 points).<BR>\n" );
document.write( "----------------------------------------------------------<BR>\n" );
document.write( " First, find the cost per unit or sale price minus cost price = C(u)<BR>\n" );
document.write( "C(u) = 100 - 50 = 50 cents per bunch<BR>\n" );
document.write( "------------------------------------------------ <BR>\n" );
document.write( "Second, find the difference of the cost price minus the price the farmer will pay = C(o)<BR>\n" );
document.write( "Note:: Sounds like the C(o) is the same as the C(u). <BR>\n" );
document.write( "Am I missing something??<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( " Third, find the purchase requirements by doing these steps: <BR>\n" );
document.write( "a. C(u)/C(o) +C(u) = P (only go out to four decimal places) (HINT: This must be less than one - if it's greater than one - you've got the division wrong...if you are banging your head against the wall...it's time to call Dr. Fenner)<BR>\n" );
document.write( " b. go to this calculator to find the normsinv (probability value) (http://easycalculation.com/statistics/inverse-cumulative-normal-standard-distribution.php). Put the number you got for a. (probability) in the top box, hit calculate and then a number will appear in the normsinv (remember this number)<BR>\n" );
document.write( " c. Then calculate the purchase by: number of bunches you sell now (number 4 above) plus Probability Value (the normsinv number from b. above) times your standard deviation (number 5 above) or<BR>\n" );
document.write( " Sales + (Probability Value (the normsinv number) times Standard Deviation) <BR>\n" );
document.write( "(Hint: notice the distribution: calculate Probability Value x Standard Deviation and then add this number to current sales)<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );