document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892467>Question 892467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the distance between the given points (1/5, 2/3) and (-2/3, -1/5)\r<BR>\n" );
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document.write( "Thank You! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540508 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540508\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the distance between the given points (1/5, 2/3) and (-2/3, -1/5) <BR>\n" );
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document.write( "d = sqrt[(-1/5 - 2/3)^2 + (-2/3)-(1/5)^2]<BR>\n" );
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document.write( "d = sqrt[(-3-10)/15)^2 + (-10-3)/15)^2]<BR>\n" );
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document.write( "d = sqrt{(-13/15)^2 + (-13/15)^2]<BR>\n" );
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document.write( "d = sqrt[2(169/225)]<BR>\n" );
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document.write( "d = (13/15)sqrt(2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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