document.write( "Question 892220: A student has 83 coins worth a total of $12.05. Each coin is either a Dime (10 cents) or a Quarter (25 cents). If x is the number of quarters, then x can be determined from the equation \n" ); document.write( "
Algebra.Com's Answer #540471 by ankor@dixie-net.com(22740)\"\" \"About 
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A student has 83 coins worth a total of $12.05.
\n" ); document.write( " Each coin is either a Dime (10 cents) or a Quarter (25 cents).
\n" ); document.write( " If x is the number of quarters, then x can be determined from the equation
\n" ); document.write( ":
\n" ); document.write( "Let y = no. of dimes
\n" ); document.write( "then
\n" ); document.write( "x + y = 83
\n" ); document.write( "and
\n" ); document.write( ".25x + .10y = 12.05
\n" ); document.write( "multiply the above equation by 10, subtract the 1st equation
\n" ); document.write( "2.5x + 1y = 120.50
\n" ); document.write( "x + y = 83
\n" ); document.write( "--------------subtraction eliminates y find x
\n" ); document.write( "1.5x = 37.5
\n" ); document.write( "x = 37.5/1.5
\n" ); document.write( "x = 25 quarters
\n" ); document.write( ":
\n" ); document.write( ";
\n" ); document.write( "To check this find the no. of quarter
\n" ); document.write( "y = 83 - 25
\n" ); document.write( "y = 58 dimes
\n" ); document.write( "Find the values
\n" ); document.write( ".25(25) + .10(58) =
\n" ); document.write( "6.25 + 5.80 = 12.05 \n" ); document.write( "
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