document.write( "Question 892378: A driver took a day trip driving at two different speeds. He drove 60 miles at a slower speed and 160 miles at a speed 10 mph faster. If the time spent during the faster speed was twice that spent at a slower speed, find the two speeds during the trip. \n" ); document.write( "
Algebra.Com's Answer #540457 by ankor@dixie-net.com(22740)\"\" \"About 
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A driver took a day trip driving at two different speeds.
\n" ); document.write( " He drove 60 miles at a slower speed and 160 miles at a speed 10 mph faster.
\n" ); document.write( " If the time spent during the faster speed was twice that spent at a slower speed, find the two speeds during the trip.
\n" ); document.write( ":
\n" ); document.write( "let s = the slower speed
\n" ); document.write( "then
\n" ); document.write( "(s+10) = the faster speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "160 mi time = twice 60 mi time
\n" ); document.write( "\"160%2F%28s%2B10%29\" = 2*\"60%2Fs\"
\n" ); document.write( "\"160%2F%28s%2B10%29\" = \"120%2Fs\"
\n" ); document.write( "cross multiply
\n" ); document.write( "160s = 120(s+10)
\n" ); document.write( "160s = 120s + 1200
\n" ); document.write( "160s - 120s = 1200
\n" ); document.write( "40s = 1200
\n" ); document.write( "s = 1200/40
\n" ); document.write( "s = 30 mph is the slow speed
\n" ); document.write( "then, obviously;
\n" ); document.write( "40 mph is the faster speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this; find the actual time at each speed
\n" ); document.write( "60/30 = 2 hrs
\n" ); document.write( "160/40 = 4 hrs\r
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