document.write( "Question 892340: If (x+2)^2 = 49 and (y+5)^2=16, then which cannot be the value of x+y?\r
\n" ); document.write( "\n" ); document.write( "a. -18
\n" ); document.write( "b. -10
\n" ); document.write( "c. -6
\n" ); document.write( "d. -4
\n" ); document.write( "e. 4
\n" ); document.write( "

Algebra.Com's Answer #540441 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"%28x%2B2%29%5E2+=+49+\"
\n" ); document.write( "\"x%2B2+=+0+%2B-+7\"
\n" ); document.write( "\"x=-2+%2B-+7\"
\n" ); document.write( "\"x=5\" and \"x=-9\"
\n" ); document.write( "and
\n" ); document.write( "\"%28y%2B5%29%5E2+=+16\"
\n" ); document.write( " \"y%2B5=0+%2B-+4\"
\n" ); document.write( "\"y=-5+%2B-+4\"
\n" ); document.write( "\"y=-1\" and \"y=-9\"
\n" ); document.write( "So then,
\n" ); document.write( "\"x%2By=5-1=4\"
\n" ); document.write( "\"x%2By=5-9=-4\"
\n" ); document.write( "\"x%2By=-9-1=-10\"
\n" ); document.write( "\"x%2By=-9-9=-18\"
\n" ); document.write( "
\n" ); document.write( "
\n" );