document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75326>Question 75326</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please provide assistance in creating the equation for this problem and also show how to solve this word problem.\r<BR>\n" );
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document.write( "Problem:  Edmund is 3 years older than Frank.  The sum of their ages is nineteen years.  How old is each one?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54044 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let E be Edmund's age and F be Frank's age.<BR>\n" );
document.write( "From the problem description, you can write:<BR>\n" );
document.write( "1) E = F+3 and<BR>\n" );
document.write( "2) E+F = 19<BR>\n" );
document.write( "Now, you substitute the E from equation 1) into equation 2) and solve for F.<BR>\n" );
document.write( "2a) (F+3) + F = 19 Simplify.<BR>\n" );
document.write( "2F+3 = 19  Subtract 3 from both sides.<BR>\n" );
document.write( "2F = 16  Divide both sides by 2.<BR>\n" );
document.write( "F = 8 This is Frank's age.<BR>\n" );
document.write( "E = F+3<BR>\n" );
document.write( "E = 8+3<BR>\n" );
document.write( "E = 11  This is Edmund's age. </SPAN>\n" );
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