document.write( "Question 892292: Please help me to solve this question :
\n" ); document.write( "If sum of 4 consecutive multiple of 6 is 125 then what are the consecutive multiples?
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Algebra.Com's Answer #540410 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Let n be an integer (maybe?).\r
\n" ); document.write( "\n" ); document.write( "\"6n%2B6%28n%2B1%29%2B6%28n%2B2%29%2B6%28n%2B3%29=125\"\r
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\n" ); document.write( "\n" ); document.write( "\"24n%2B6%2B12%2B18=125\"
\n" ); document.write( "\"24n%2B36=125\"
\n" ); document.write( "\"24n=125-36\"
\n" ); document.write( "\"24n=89\"
\n" ); document.write( "\"n=89%2F24\"
\n" ); document.write( "n is NOT an integer.\r
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\n" ); document.write( "\n" ); document.write( "The four multiples of six are 89/4, ....
\n" ); document.write( "No. I am stopping there.
\n" ); document.write( "Are you SURE you have the correct problem description? What do you mean by \"consecutive multiples\"? Does each multiple of 6 differ by 1? If so, then the next or last three numbers are \"6%2889%2F24%2B1%29\", \"6%2889%2F24%2B2%29\", and \"6%2889%2F24%2B3%29\".
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