document.write( "Question 75314This question is from textbook Alegbra 2 An Incremental Development
\n" ); document.write( ": PLease help to factor :\r
\n" ); document.write( "\n" ); document.write( "64a^3c^6 + x^6y^9
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Algebra.Com's Answer #54041 by Earlsdon(6294)\"\" \"About 
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Factor\"
\n" ); document.write( "\"64a%5E3c%5E6%2Bx%5E6y%5E9\" Do you recognise this as the sum of two cubes?
\n" ); document.write( "\"%284ac%5E2%29%5E3%2B%28x%5E2y%5E3%29%5E3\"
\n" ); document.write( "The sum of two cubes can be factored thus:
\n" ); document.write( "\"A%5E3%2BB%5E3+=+%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\" Applying this to your expression, where:\"A+=+4ac%5E2\" and \"B+=+x%5E2y%5E3\", we get:
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