document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892198>Question 892198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> bob is traveling in a canoe that can go downstream at 6 km/h and upstream at 2 km/h. If she starts upstream and wishes to return to the starting point in exactly 4 hours. How far should he travel upstream? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540362 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> bob is traveling in a canoe that can go downstream at 6 km/h and upstream at 2 km/h. If she starts upstream and wishes to return to the starting point in exactly 4 hours. How far should he travel upstream?<BR>\n" );
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document.write( "let x=hours Bob travels upstream<BR>\n" );
document.write( "4-x=hours Bob travels downstream<BR>\n" );
document.write( "distance=speed*travel time<BR>\n" );
document.write( "2x=6(4-x)<BR>\n" );
document.write( "2x=24-6x<BR>\n" );
document.write( "8x=24<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "2x=6<BR>\n" );
document.write( "How far should he travel upstream? 6 km </SPAN>\n" );
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