document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=892149>Question 892149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how can a negative antilog be solve?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #540318 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=540318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the definition of antilog from the dictionary is:\r<BR>\n" );
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document.write( "The number whose logarithm is a given number. \r<BR>\n" );
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document.write( "For example, the logarithm of 1,000 is 3 because 10^3 = 1000, so the antilogarithm of 3 is 1,000.\r<BR>\n" );
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document.write( "per the definition, it's the number whose logarithm is a given number.\r<BR>\n" );
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document.write( "the number is 1000.<BR>\n" );
document.write( "the logarithm of 1000 is equal to 3.<BR>\n" );
document.write( "the number whose logarithm to the base of 10 is 3, is 1000.\r<BR>\n" );
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document.write( "your question is how can a negative antilog be solved.\r<BR>\n" );
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document.write( "the log of a number can itself be negative.\r<BR>\n" );
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document.write( "for example, the log of (1/1000) is equal to -3 because 10^-3 = 1/1000.\r<BR>\n" );
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document.write( "to find the antilog of -3, you need to find the number whose logarithm is -3.\r<BR>\n" );
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document.write( "since the base is 10, you are then looking for 10^-3 = .001 = 1/1000.\r<BR>\n" );
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document.write( "another example:\r<BR>\n" );
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document.write( "log to the base of 2 of (1/32) is equal to -5 because 2^-5 = 1/2^5 = 1/32.\r<BR>\n" );
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document.write( "the antilog of -5 to the base of 2 is 2^-5 = 1/32.\r<BR>\n" );
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document.write( "1/32 is the antilog of -5 with a base of 2.\r<BR>\n" );
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document.write( "if the base is not 10, it needs to be specified.\r<BR>\n" );
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document.write( "antilog of -3 is assumed to be 10^-3 because the base was not specified and so it's assumed to be 10.\r<BR>\n" );
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document.write( "antilog of -5 to the base of 3 would be equal to 3^-5 = 1/3^5 = 1/243.\r<BR>\n" );
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document.write( "the antilog of -5 to the base of 3 would be equal to 1/243 because the log to the base of 3 of (1/243) is equal to -5.\r<BR>\n" );
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document.write( "you can find the log of another base other than 10 using your calculator by using the base conversion formula.\r<BR>\n" );
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document.write( "log of any base can be found using the base of 10 by the following conversion formula.\r<BR>\n" );
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document.write( "loga(x) = log10(x)/log10(a)\r<BR>\n" );
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document.write( "example:\r<BR>\n" );
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document.write( "log3(1/243) = log10(1/243)/log10(3) = LOG(1/243)/LOG(3), where LOG means log10 and LOG is the log key on your calculator.\r<BR>\n" );
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document.write( "try it on your calculator.\r<BR>\n" );
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document.write( "log3(1/243) = LOG(1/243)/LOG(3).\r<BR>\n" );
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document.write( "you will get -5.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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