document.write( "Question 892116: After robbing a bank in Dodge City, a robber gallops off at 14 mi/h. 20 minutes later, the marshall leaves to pursue the robber at 15 mi/h. How long (in hours) does it take the marshall to catch up to the robber? \n" ); document.write( "
Algebra.Com's Answer #540294 by robertb(5830)\"\" \"About 
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Let x = # of hours it takes for the marshall to catch up with the robber.
\n" ); document.write( "Then x + 1/3 = # of hours the robber has been on the run before he is caught.\r
\n" ); document.write( "\n" ); document.write( "==> \"14%28x%2B1%2F3%29+=+15x\"
\n" ); document.write( "==> \"14x+%2B+14%2F3+=+15x\"
\n" ); document.write( "==> \"x+=+14%2F3\" hours, or after 4 hours and 40 minutes.
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